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how opendaylight determines 2 nodes are connected

asked 2014-06-11 12:00:20 -0700

anonymous user

Anonymous

I understand that might be a question more related to the controller, but at this point, i am not sure.

So, basically, i have such a configuration:

-------- --------- ---------------- | A | -eth0--> eth0 -| B | -eth4 ----- LAN ------eth4 | Controller | -------- --------- -----------------

node A and B are 2 ovs-switch.... I can get both A and B to connect to the controller, but the controller, in my case OpenDaylight, does not draw a line between A and B in the GUI... meaning it doens't know they are connected together, right?.... how can we have both connected? If i had a br0:1 interface on A with the LAN subnet that is between B and the controller, it shows that br0:1 address as a host connected to B for that address.

Anyone knows why it doesn't see a link between A and B or why it sees br0:1 as a host? Does anyone know how the controller determines if 2 nodes are connected to each other (in my case I would expect it to see that eth0 in br0 of A is connected to eth0 in br0 of B)... maybe by knowing that i could fix that up ...

thanks,

sorry to ask anonymously, but i was not able to register... i have to give it a try again... but i didn't want to wait before posting my question.

sam

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answered 2014-06-11 13:14:23 -0700

Moderators

The controller build up the topography by LLDP between the switches. But there has to be a flow or default feature of the LLDP packet being sent to the controller.

As for End Host this but the controller processing the ARP packets.

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Asked: 2014-06-11 12:00:20 -0700

Seen: 394 times

Last updated: Jun 11 '14